Number Of Neutrons In Oxygen

ii) Calculate number of protons and neutrons from isotopes of Oxygen¹⁶O,¹⁷O, and¹⁸O. The atomic number of Oxygen is 8.

Solution:

The Atomic Number (Z) of Oxygen is 8. The atomic number is always equal to the number of protons. And the number of protons always equals the electron number in an uncharged atom so that the atom is electrically neutral.

Therefore, an uncharged Oxygen cantlet always has eight protons and 8 electrons.

 An isotope is formed when the neutron number varies in an atom of the aforementioned element. This changes the mass number in an atom's nucleus since the mass number A is the sum of protons and neutrons. The proton number remains unchanged.

 mass number A= Number of protons (p) + number of neutrons (due north)

 The mass number is written as a superscript next to the element's symbol as,

And so, the number of neutrons in different Oxygen isotopes¹⁶O,¹⁷O, and ^eighteenO is-

¹⁶ O Isotope:

Mass number =16 (Given)

mass number (A) = number of protons (p) + number of neutrons (n)

A= p+ n

Therefore, due north= A-p = xvi-8 = 8.

Solution using log table-

due north = A-p

Applying log_x on both sides

log₁₀ n = log (A-Z)

log_tenn = log₁₀ (sixteen-8) = log₁₀viii = 0.9031

Applying antilog,

n = Antilog (0.9031) = 8

The number of neutrons in the^thirteenNorthward Isotope is eight, and the number of protons is viii.

¹⁷ O Isotope:

Mass number = 17 (Given)

mass number (A) = number of protons (p) + number of neutrons (n)

A= p+ n

Therefore, n= A-p = 17-8 = 9.

Solution using log table-

n = A-p

Applying log₁₀ on both sides

log₁₀ northward = log (A-Z)

log₁₀n = log₁₀ (17-viii) = log₁₀9 = 0.9542

Applying antilog,

northward = Antilog (0.9542) = 9

The number of neutrons in the¹⁷O Isotope is 9, and the number of protons is 8.

¹⁸ O Isotope:

Mass number =17 (Given)

mass number (A) = number of protons (p) + number of neutrons (n)

A= p+ northward

Therefore, n= A-p = 18-viii = ten.

Solution using log tabular array-

n = A-p

Applying log₁₀ on both sides

log_x n = log (A-Z)

log_tendue north = log₁₀ (18-8) = log₁₀ten = i

Applying antilog,

northward = Antilog (1) = x

The number of neutrons in the^eighteenO Isotope is 10, and the number of protons is 8.

Number Of Neutrons In Oxygen,

Source: https://www.curlyarrows.com/calculate-number-proton-neutron-oxygen-isotopes-16O-17O-18O

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